Difference between revisions of "String exploding"
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− | + | The following function is an alternative which will omit empty strings from the returned table if a delimiter(s) is leading or trailing the string being exploded. This means it will return a more compact table in some cases where the input string has excessive delimiters. Due to these omissions, you won't be able to use table.concat to reverse it back into the original string. | |
<source lang="lua"> | <source lang="lua"> |
Revision as of 00:57, 6 April 2015
This function adds the ability to explode strings in Lua.
function string.explode(str, div)
assert(type(str) == "string" and type(div) == "string", "invalid arguments")
local o = {}
while true do
local pos1,pos2 = str:find(div)
if not pos1 then
o[#o+1] = str
break
end
o[#o+1],str = str:sub(1,pos1-1),str:sub(pos2+1)
end
return o
end
Have an example:
tbl = string.explode("foo bar", " ")
print(tbl[1]) --> foo
-- since we added explode to the string table, we can also do this:
str = "foo bar"
tbl2 = str:explode(" ")
print(tbl2[2]) --> bar
-- to restore the original string, we can use Lua's table.concat:
original = table.concat(tbl, " ")
print(original) --> foo bar
The following function is an alternative which will omit empty strings from the returned table if a delimiter(s) is leading or trailing the string being exploded. This means it will return a more compact table in some cases where the input string has excessive delimiters. Due to these omissions, you won't be able to use table.concat to reverse it back into the original string.
function string.explode2(s, d)
local t = {}
repeat
local pos1, pos2 = string.find(s, d)
t[#t + 1] = string.sub(s, 1, pos1 - 1)
s = string.sub(s, pos2 + 1)
until pos1 == nil
if #s ~= 0 then t[#t+1] = s end
return t
end