LÖVE

Without rewriting everything for Player 2. I've tried so many things I've already lost count... Dx

Instead of "p1" use just indexes, i.e. define them as: Use a for loop from 1 to 2 to create each player the same if you need. Then change each players specifically different data, like location on screen if you need to. i.e.: Then you can just use a for loop to go through each player: A benefit is you can add more players easily since #player returns the index count of the player table's children.

Jasoco wrote:Instead of "p1" use just indexes, i.e. define them as:

Code: Select all

player = {
  [1] = { stuff },
  [2] = { stuff }
}

Use a for loop from 1 to 2 to create each player the same if you need. Then change each players specifically different data, like location on screen if you need to. i.e.:

Code: Select all

player = {}
for i = 1, 2 do
  player[i] = { stuff }
end

Then you can just use a for loop to go through each player:

Code: Select all

for i = 1, #player do
if player[i].state == "jumping" then
      player[i].y = player[i].y + player[i].y_vel * dt
      player[i].y_vel = player[i].y_vel + gravity * dt
      if player[i].y + player[i].h > floor.y then
         player[i].y = floor.y - player[i].h
         player[i].state = "idle"
         player[i].y_vel = player[i].y_vel_base
      end
   end
end

A benefit is you can add more players easily since #player returns the index count of the player table's children.

oh wow I was actually pretty close with some of my tries LOL I just didn't index the player when initialising them :S

Thanks so much!