LÖVE

In an easy version of this, there used to be something used to delay: wait()-- number of seconds here


How would I do it in this?

It says nil when I try

Thanks for anyone willing, I hope this is not complicated

I have found this:
... so that a thread can block for a specified amount of time. In love.run, waiting is needed before running the main loop again. Threads can call wait ... M = {} local timers = {} local callbacks = {} function M.start(name, delay, callback) timers[name] = delay callbacks[name] = callback end function ...
by Inny
on Fri Oct 12, 2012 10:32 pm

Forum: Support and Development
Topic: Does love have a 'wait()'?
Replies: 5
Views: 315


Can someone give me a more thorough explanation?
I really have no idea what this is saying.
I started love.lua yesterday and I am quite new

Hi and welcome to our forum.

In the future, please be a bit more patient and wait for an answer a little longer before you post again. You cannot expect us to respond within half an hour. Also, please avoid double posting (you can edit your entries, if you forgot a line).

Now for your question:
If you want to have a delay, then you should not use a wait function. It would stop the whole program and make it unresponsive. Instead, use a timer and dt to measure time. This could be implemented like this:
To begin the delay do this: and in the loop that you want to delay you do this:

What does dt do?

Thank you, I have made my script, but now it has an error when I try to run it:


function attack2(dt)
divident = 10
timer = 0
repeat timer = timer + dt/dividend until timer == 0.1
if timer == 0.1 then
timer = 0
Bullet = love.graphics.draw(bullet,xpos,ypos - less)
Bullet = nil
end
timer2 = 0
repeat timer2 = timer2 + dt/dividend until timer == 0.1
if timer2 == 0.1 then
timer = 0
EXP1 = love.graphics.draw(exp1,xpos,ypos - less)
timer2 = 0
end
timer3 = 0
repeat timer3 = timer3 + dt/dividend until timer3 == 0.1
if timer3 == 0.1 then
timer3 = 0
EXP2 = love.graphics.draw(exp2,xpos,ypos - less)
end
timer4 = 0
repeat timer4 = timer4 + dt/dividend until timer4 == 0.1
if timer4 == 0.1 then
timer4 = 0
EXP3 = love.graphics.draw(exp3,xpos,ypos - less)
end
repeat timer5 = timer5 + dt/dividend until timer5 == 0.1
if timer5 == 0.1 then
timer5 = 0
EXP1 = nil
end
timer6 = 0
repeat timer6 = timer6 + dt/dividend until timer6 == 0.1
if timer6 == 0.1 then
timer6 = 0
EXP2 = nil
end
timer7 = 0
repeat timer7 = timer7 + dt/dividend until timer7 == 0.1
if timer7 == 0.1 then
timer7 = 0
EXP3 = nil
end
end



Error says: attempt to perform arithmetic on local 'dt' ( a nil value')


All of your help is appreciated!
Just remember, I am new, so please, pardon my errors

Can we see where and how you call attack2? You should call it inside love.update, passing dt to it as argument: Also, please use the

Your code, though will not make a delay.
This repeat-loop will just add up some numbers in a split second and you will not notice a delay.

You have misunderstood the concept of making a delay. To make a delay, you should NOT try to change the time it takes to do one game-loop (update + draw), but instead you should keep the game loop running and in each iteration do nothing and then after the time is over, do the next action.

Can you give an example of that, or remake my code that way?
I am quite confused.