Removing Specific Subtables?

[WolfNinja2]

How can I do this, when I add the subtable it is set up with and X,Y,Direction and ID.
I was thinking maybe something like this

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table.remove(enemy)(ID)

????
I have no idea though :/

-Wolf

[keharriso]

If you mean to say that enemy.ID is set to some value, then all you have to do is:

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enemy.ID = nil

Just set a field to nil to get rid of it!

If this isn't what you meant, it'd be useful to get a more specific description. Show the code where you create and add the subtable.

[Qcode]

I don't see a good reason to use table.remove in this situation. Table.remove is mainly meant for tables where you're not defining each value with a string key. When you use table.remove, it removes the value in the table specified, then moves all the other tables down one to compensate. Since you don't need to do this, as you're using keys such as x, y, direction and id it would be much easier to just set id to nil.
Try and see if this bit of code works:

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for i = #enemy, 1, -1 do
     enemy[i].ID = nil
end

~Qcode

Edit: Ninja'd by keharriso. Oh well.

[WolfNinja2]

When the enemy is created it looks like this, in fact here is the whole enemy code.

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enemy = {}

function enemycreate(x,y,direction,id)
	table.insert(enemy,{x=x,y=y,direction=direction,id=id,speed = 240,h = 32,w = 32})
end

function enemyupdate(dt)
	for i,v in ipairs(enemy) do
   if v.direction == "right" then
      v.x = v.x + v.speed * dt
   end
   if v.direction == "left" then
     v.x = v.x - v.speed * dt
		end
	end
end

function enemycollide(dt)
	for i,v in ipairs(enemy) do
	
		E_timedspeed = v.speed * dt
	
		if E_mapCollide(v.x - E_timedspeed, v.y + 1) or B_mapCollide(v.x - E_timedspeed, v.y + v.h - 1) then
		v.x = math.floor(v.x / tiledivisor) * tiledivisor
		v.direction = "right"
		v.x = v.x + 32
		end
		if E_mapCollide(v.x + E_timedspeed + v.w, v.y + 1) or B_mapCollide(v.x + E_timedspeed + v.w, v.y + v.h - 1) then
		v.x = (math.floor((v.x + v.w + E_timedspeed) / tiledivisor) * tiledivisor) - v.w
		v.x = v.x - 32
		v.direction = "left"
		end
	end
end

function enemy_draw()
for i,v in ipairs(enemy) do
	g.setColor(255,255,255,255)
	g.draw(E, v.x, v.y, 0, 1, 1)
	end
end

function enemy_die(dt)
	for i,v in ipairs(enemy) do
		if B_x > v.x and
			B_x < v.x + v.w and
			B_y > v.y and
			B_y < v.y + v.h then
			print "hyeap"
			if v.id == 1 then
			table.remove(enemy,1)
			end
			if v.id == 2 then
			table.remove(enemy,2)
			end
		end
	end
end

And here is where they are spawned.

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if gamestate == "lvl 3" and
	enemyloaded == false then
	enemycreate(128,32,"right",1)
	enemycreate(256,32,"left",2)
	enemyloaded = true
	end

Sorry I was so unspecific :/

EDIT: This coding removes one of the enemies but the other doesn't die.... Just thought it may be helpful to know.

-Wolf

[Qcode]

Have you tried both of our solutions? Because that error sounds like something that would happen without using a reverse loop. Try my code if you haven't.

[WolfNinja2]

Have you tried both of our solutions? Because that error sounds like something that would happen without using a reverse loop. Try my code if you haven't.

Now niether remove :/

[Qcode]

Are you trying to remove the id or the actual enemy table? If you're trying to remove the table why don't you just have an v.remove value?

[WolfNinja2]

so

if v.remove == true then

..... How would i end it ( exactly )

[Qcode]

I'd do the remove function like this:

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for i = #enemy, 1, -1 do
     if enemy[i].remove then
          table.remove(enemy, i)
     end
end

Is that what you're looking for?

[WolfNinja2]

I'd do the remove function like this:

Code: Select all

for i = #enemy, 1, -1 do
     if enemy[i].remove then
          table.remove(enemy, i)
     end
end

Is that what you're looking for?

I'll try it, now what does all that mean? for i = #enemy, (this calls the table right? ) but then after that what does 1,-1 mean
and enemy.remove is that just checking if v.remove is true?
Sorry for being a nuisance ;/

-Wolf