Load image from different directory

[PartyCow]

If a image is in another folder than the script, how will I load it?

Thanks

[Robin]

If you're saying what I think you're saying then you can't.

Otherwise: suppose your game is at "(....)/mygame/". Then your main.lua would need to be at "(....)/mygame/main.lua". If you have an image at "(....)/mygame/images/background.png", you would load it as:

Code: Select all

background = love.graphics.newImage("images/background.png")

[MoseGames]

this should work:

Code: Select all

local file = io.open(self:path(path) , "r")
local contents = file:read("*all")
local data = love.filesystem.newFileData( contents, "img.png", "file" )
local imgdata = love.image.newImageData( data )

file:close()

local img = love.graphics.rawNewImage( imgdata )

It's a bit long, but it worked for me.

[zorg]

this should work:

Code: Select all

local file = io.open(self:path(path) , "r")
local contents = file:read("*all")
local data = love.filesystem.newFileData( contents, "img.png", "file" )
local imgdata = love.image.newImageData( data )
file:close()
local img = love.graphics.rawNewImage( imgdata )

It's a bit long, but it worked for me.

This is neat and all, but what's self in that context?
Also, what's love.graphics.rawNewImage??? last i checked, only love.graphics.newImage exists.

Anyway, io.open(path, 'r') is fine, since it does take a path, no need to make it complicated.

That said, you should only use lua's io functions if you want to access files from directories ABOVE/OUTSIDE the one where your main.lua is; if it's a sub-directory, then you can access those simply by doing love.image.newImage('subfolder/image.png').