Read the contents of folder

[vladislavbyk]

How can I read the contents of a specific folder without file extensions?

[josefnpat]

Try using love.filesystem.enumerate

edit:

Then use Lua pattern matching to remove the extension

[vladislavbyk]

Then use Lua pattern matching to remove the extension

How..?

[josefnpat]

Then use Lua pattern matching to remove the extension

How..? :)

Take a look at the documentation.

[vladislavbyk]

Then use Lua pattern matching to remove the extension

How..?

Take a look at the documentation.

I really do not understand how it works It's hard in lua..

[dreadkillz]

I hate to be THAT guy, but you'll have to do some experimenting to really get it. Go open the Lua interpreter in a terminal/commandline and start messing around with strings.

[Roland_Yonaba]

Using Lua pattern matching is not as complicated as you might think it is.
Some indications:
You can use string.gsub().
- First arg will be the filename,
- Second will be the pattern to capture the extension, to be replaced with the third argument.
- Third argument will be the empty string.

Now, have in mind that a file extension starts with a dot, followed by one or more characters (letters/numbers), and is anchored at the end of the full filename.

Hope that helps.

[BlackBulletIV]

Here's the code for what Roland is saying:

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string.gsub(filename, "%.%w+$", "")

You may want to add support for hyphens for extensions like .sublime-project:

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string.gsub(filename, "%.([%w%-]+)$", "")

[vladislavbyk]

Thanks guys

[kikito]

Come on guys. Lua's patterns have always been difficult. Give vlad a break.

Besides, getting the pattern is actually tricker than it looks. BlackBulletV, who is very experienced with Lua, got it wrong (his pattern will fail with files with a double extension, such as myfile.tar.gz).

Here's what I'd use to get the file name only (this is what vlad needs - probably there's a simpler pattern, but this one works very well):

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function getBasename(filename)
  return filename:match("^([^%.]*)%.?") -- "myfile.lua" -> "myfile"
end

Here's an extended version (compatible with the previous one) which does a little more; it returns the corresponding extension:

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function getBasenameAndExtension(filename)
  return filename:match("^([^%.]*)%.?(.*)$") -- "myfile.lua" -> "myfile", "lua"
end

Tests:

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for _,filename in ipairs({"myfile.lua", "myfile", ".bashrc", "myfile.tar.gz", "myfile.yeah-baby.yeah"}) do
  print(("getBasename(%q) = %q"):format(filename, getBasename(filename)))
  print(("getBasenameAndExtension(%q) = %q, %q"):format(filename, getBasenameAndExtension(filename)))
end

Result:

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getBasename("myfile.lua") = "myfile"
getBasenameAndExtension("myfile.lua") = "myfile", "lua"
getBasename("myfile") = "myfile"
getBasenameAndExtension("myfile") = "myfile", ""
getBasename(".bashrc") = ""
getBasenameAndExtension(".bashrc") = "", "bashrc"
getBasename("myfile.tar.gz") = "myfile"
getBasenameAndExtension("myfile.tar.gz") = "myfile", "tar.gz"
getBasename("myfile.yeah-baby.yeah") = "myfile"
getBasenameAndExtension("myfile.yeah-baby.yeah") = "myfile", "yeah-baby.yeah"