How to remove images?

[Wittloc]

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function love.load()
	freddyA = love.graphics.newImage("431.png")
	staticA = love.graphics.newImage("590.png")
	staticB = love.graphics.newImage("591.png")
	staticC = love.graphics.newImage("592.png")
	staticD = love.graphics.newImage("593.png")
	sound = love.audio.newSource("staticB.wav")
	music = love.audio.newSource("menu.wav")
	sound:play()
	music:play()
end

function love.draw()
	love.graphics.draw(freddyA)
	love.graphics.draw(staticA)
end

I want to remove staticA to put staticB after a few seconds, to make a static effect. How do I remove drawn images?

[DmL]

In your love.load() you'll want to assign a variable like "currentImage"

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currentImage = staticA

In your love.draw() you want to draw your currentImage

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love.graphics.draw(currentImage, 0, 0)

Then you'll need a callback to load.update(dt)
There you can assign the current time to a local variable.
Then, in an if statement, you can check to see if a certain amount of time has passed, and if so, you can change your currentImage
Something like:

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love.update(dt) -- The dt is the time which has passed since this was last called.  Probably we don't need this right now.
local oldTime = love.timer.getTime()

if (love.timer.getTime() >= oldTime + 1) then -- I believe the 1 should stand for one second, in this case.  Is the new time 1 second more than the old time?
currentImage = staticB
end

That would switch out A for B after 1 second. To switch back and forth, you would add another if statement in that block. To shuffle through all of the images, add them to a table and interate through it!

Hope this helps. I'm not a programmer, so there is probably a bug, but this is the basic idea.

[zorg]

Code: Select all

love.update(dt) -- The dt is the time which has passed since this was last called.  Probably we don't need this right now.
local oldTime = love.timer.getTime()

if (love.timer.getTime() >= oldTime + 1) then -- I believe the 1 should stand for one second, in this case.  Is the new time 1 second more than the old time?
currentImage = staticB
end

That won't work, since the oldTime will be overwritten every frame as well; you want this instead:

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local time = 0
function love.update(dt)
time = time + dt
if time > 1 then
currentImage = staticB
end
end

[DmL]

I'm still learning Lua, but I had a feeling that would be the case. You could also do an

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if (oldTime == nil) then
local oldTime -- etc

[zorg]

...You could also do an

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if (oldTime == nil) then
local oldTime -- etc

The problem with that is that no one is stopping you from defining a global oldTime variable elsewhere; if it _is_ defined, it will never swap.
...Actually, the bigger issue is that you'd be defining the local inside the if's scope, and not the function's.

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function love.update(dt)
local oldTime
if oldTime == nil then
-- ...even if i could transform this so it seemed to work, i don't know whether only defining oldTime as a local will set it to something, or allow through some hackery what i've written before.

[Wittloc]

Code: Select all

love.update(dt) -- The dt is the time which has passed since this was last called.  Probably we don't need this right now.
local oldTime = love.timer.getTime()

if (love.timer.getTime() >= oldTime + 1) then -- I believe the 1 should stand for one second, in this case.  Is the new time 1 second more than the old time?
currentImage = staticB
end

That won't work, since the oldTime will be overwritten every frame as well; you want this instead:

Code: Select all

local time = 0
function love.update(dt)
time = time + dt
if time > 1 then
currentImage = staticB
end
end

So, if I wanted it to switch from A to B to C to D then repeat, what would I use?

[zorg]

You could do:

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local t = {}
local current = 1
local delay = 1.0 -- seconds

function love.load()
	t[1] = love.graphics.newImage("590.png")
	t[2] = love.graphics.newImage("591.png")
	t[3] = love.graphics.newImage("592.png")
	t[4] = love.graphics.newImage("593.png")
	-- ...
end

function love.draw()
	love.graphics.draw(t[current], 0, 0)
end

local time = 0
	function love.update(dt)
	time = time + dt
	if time > delay then
		current = (current % #t) + 1 -- increase with wrap, think "i = i + 1" with i always being between 1 and the number of elements inclusive.
		time = time - delay
	end
end

for example.

[Dattorz]

If you want to "erase" an image that has been drawn to the screen, all you have to do is not draw it on the next frame.

Every time the game gets ready to draw, by default the screen will be cleared to the background color by calling love.graphics.clear(). This is done for you and you don't need to call this yourself unless of course you have overwritten love.run().

As other have mentioned, if you want to create the impression of animation, you just change the image that you draw with to something else. If you're stuck on this, there are tutorials and helper libraries that can do this for you.

[DmL]

Actually, the bigger issue is that you'd be defining the local inside the if's

Huh. True, thanks for the pointer.