Well, a bit, but I still don't know e.g. what enemy collided with the player, how can I do that?

Hey! Are there any neat ways to wrap the different collision scenarios into maintanable and extendable code? In C++, for instance, I would probably add a virtual method to a class. How can I achieve this using HC? Basically what I want to do is identify e.g. what enemy is colliding with e.g. the wal...

Well, you could make a function that convert HSL into RGB.

https://love2d.org/wiki/HSL_color

Jasoco wrote:

nordbjerg wrote:Dear Illuminati,

What is this about?

Sincerely,
concerned customer #125914

Actually you're number 123330. Not 125914.

Oh, yes. I apologize.

Dear Illuminati,

What is this about?

Sincerely,
concerned customer #125914

... If this still does not work (rounding errors, maybe) then you can introduce an angular tolerance, which is a maximum overlap that is allowed: function arccollision (mid1, width1, mid2, width2) delta = math.abs( (mid1-mid2+math.pi)%(2*math.pi)-math.pi) if delta <= (width1+width2)/2 - tolerance t...

I added your code and it worked great in any other case than this: p:addSegment(math.pi * 2.5, math.pi / 2, 255, 0, 0) p:addSegment(math.pi * 2, math.pi / 2, 0, 0, 255) p:addSegment(math.pi, math.pi, 0, 255, 0) If I do math.pi / 2.05 it works, otherwise it will not fit. The syntax is pie:addSegment(...

You are dealing with angles here, but it works the same way as with intervals (lines). Let's say you have two intervals (a,b) and (c,d). How do you check if they overlap? It is easier to check if the do not overlap: There are only two cases possible: Either it is b < c or it is a > d. So, if you ha...

Hey LÖVErs! :neko: I need a way to check if two arcs occupy the same space in a given circle, but I am unsure of how to go about it. The idea is that I can create nodes off of other nodes in my game, with each node having a specific arc / cirlce segment size. Of course, these segments must not occup...

davisdude wrote:love.graphics.arc.()
They have an example of how to draw pacman!

Yes! This is what I was looking for

Thank you kindly, sir!